A) \[\sqrt{8}+\sqrt{22}\]
B) \[\sqrt{1}+\sqrt{29}\]
C) \[\sqrt{12}+\sqrt{18}\]
D) \[\sqrt{10}+\sqrt{20}\]
Correct Answer: C
Solution :
\[{{(\sqrt{8}+\sqrt{22})}^{2}}=30+2\sqrt{176}\] \[{{(\sqrt{1}+\sqrt{29})}^{2}}=30+2\sqrt{29}\] \[{{(\sqrt{12}+\sqrt{18})}^{2}}=30+2\sqrt{216}\] \[{{(\sqrt{10}+\sqrt{20})}^{2}}=30+2\sqrt{200}\] Thus, \[\sqrt{12}+\sqrt{18}\] is greatest.
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