A) 39
B) 40
C) 41
D) 42
Correct Answer: D
Solution :
Here, \[a=2,\,\,d=4-2=2\] and \[n=6\] \[\therefore \] \[{{S}_{n}}=\frac{n}{2}[2a+(n-1)d]\] \[{{S}_{6}}=\frac{6}{2}[2\times 2+(6-1)\times 2]\] \[=3\,(4+5\times 2)=3\,(4+10)\] \[=3\times 14=42\]
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