A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{3}{4}\]
D) \[\frac{4}{5}\]
Correct Answer: C
Solution :
Since, one root of the equation \[a{{x}^{2}}+x-3=0\] -1. \[\therefore \] \[a{{(-1)}^{2}}+(-1)-3=0\] \[\Rightarrow \] \[a-4=0\] \[\Rightarrow \] \[a=4\] So, the equation is \[4{{x}^{2}}+x-3=0\]. Let the other root of this equation is a. \[\therefore \] Product of roots \[=-1\cdot \alpha \] \[\Rightarrow \] \[\frac{-3}{4}=-\alpha \] \[\Rightarrow \] \[\alpha =\frac{3}{4}\]
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