A) 12 men
B) 15 men
C) 17 men
D) 11 men
E) 9 men
Correct Answer: B
Solution :
We have \[{{M}_{1}}=8,\]\[{{W}_{1}}=\frac{2}{5},\]\[{{D}_{1}}=10\]\[{{M}_{2}}=?,\]\[{{W}_{2}}=\frac{3}{5},\]\[{{D}_{2}}=8\] \[{{M}_{1}}{{D}_{1}}{{W}_{2}}={{M}_{2}}{{D}_{2}}{{W}_{1}}\] or, \[8\times 10\times \frac{3}{5}={{M}_{2}}\times 8\times \frac{2}{5}\] \[\therefore \]\[{{M}_{2}}=3\times 5=15\,men\]
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