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Banking Sample Paper IBPS Clerk (PT) Sample Paper Test-1

  • question_answer
    Two pipes P and Q fill a circular tank in 56 and 42 hours respectively while a third pipe R can empty it in 72 hours. If all three pipes are opened together then what time will they take to fill the tank?

    A)  26 hours                      

    B)  2 8 hours         

    C)  36 hours          

    D)    42 hours          

    E)  None of these

    Correct Answer: C

    Solution :

    Part of the tank filled in 1 hour when all 3 pipes are open =\[\left( \frac{1}{56}+\frac{1}{42}-\frac{1}{72} \right)\]\[=\frac{14}{504}\] \[\therefore \]Reqd time \[=\frac{504}{14}hours=36\,hours\] Alternative Method: LCM of 56, 42 and 72 = 504 Let the capacity of the tank be 504 units. Then Pipe A can fill in one hour\[=\frac{504}{56}=9\,units\] Pipe B can fill in one hour\[=\frac{504}{42}=12\,\,units\] Pipe C can empty in one hour\[=\frac{504}{72}=7\,\,units\] \[\therefore \] All pipes fill 504 units in \[\left( \frac{504}{9+12-7}= \right)\] \[\frac{504}{14}hours=36\,hours\]


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