| Direction: Study the following information carefully and answer the question given below: |
| In a bag, there are some balls of three different colours, i.e. red, green and blue. The number of blue balls is 10 while the probability of getting a green ball is \[\frac{1}{2}\] and the probability of getting a red ball is\[\frac{2}{9}\]. |
A) \[\frac{891}{7190}\]
B) \[\frac{62}{447}\]
C) \[\frac{31}{223}\]
D) \[\frac{248}{1785}\]
E) \[\frac{615}{731}\]
Correct Answer: D
Solution :
Having Green balls = \[^{18}{{C}_{3}}\] Having Red balls =\[^{8}{{C}_{3}}\] Having Blue balls = \[^{10}{{C}_{3}}\] So reqd probability \[=\frac{{}^{18}{{C}_{3}}+{}^{8}{{C}_{3}}+{}^{10}{{C}_{3}}}{{}^{36}{{C}_{3}}}=\frac{992}{7140}=\frac{248}{1785}\]
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