A) \[\frac{5}{6}\]
B) \[\frac{1}{6}\]
C) \[\frac{1}{36}\]
D) \[\frac{91}{216}\]
E) \[\frac{125}{216}\]
Correct Answer: D
Solution :
Total no. of possibilities of 3 dice\[={{6}^{3}}=216\] To find at least 1 six, we find the no. of six as \[\frac{5}{6}\times \frac{5}{6}\times \frac{5}{6}=\frac{125}{216}\] \[\therefore \] At least 1 six \[=1-\frac{125}{216}=\frac{91}{216}\]
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