question_answer

Direction: In the following questions two equations numbered I and II have been given. Solve both the equations and give answer.

I. \[{{x}^{2}}+16x=-63\] II. \[3{{y}^{2}}+32y+45=0\]

A)  \[x<y\]

B)  \[x>y\]

C)  \[x=y\] or no relation can be established

D)  \[x<y\]

E)  \[x>y\]

Correct Answer: C

Solution :

  Step II & III. \[x=-9,-7\] Step II. \[\frac{27}{3},\frac{5}{3}\] Step III. \[y=-9,-\frac{5}{3}\] Hence relationship can't be determined.