question_answer

Direction: In the following questions two equations numbered I and II have been given. Solve both the equations and give answer.

I. \[4{{x}^{2}}+16x+15=0\]     II. \[17{{y}^{2}}+20y+3=0\]

A)  \[x<y\]

B)  \[x>y\]

C)  \[x=y\] or no relation can be established

D)  \[x<y\]

E)  \[x>y\]

Correct Answer: D

Solution :

  Step II. \[\frac{10}{4}\]       \[\frac{6}{4}\] Step III. \[x=-25-1.5\] Step II.    \[\frac{17}{17}\frac{3}{17}\] Step III. \[y=-1,-\frac{3}{17}\] Hence \[x<y\]