A) 4
B) 12
C) 8
D) 6
Correct Answer: D
Solution :
[d]: Here, \[l=85\text{ }cm=0.85m,v=340\text{ }m\text{ }{{s}^{-}}^{1}\] Pipe is closed from one end so it behaves as a closed organ pipe. Frequencies in the closed organ pipe is given by, \[\upsilon =\frac{(2n-1)v}{4l}\]where, n = 1, 2, 3, 4,........... According to question,\[\upsilon <1250Hz\] \[\left( \frac{2n-1}{4l} \right)v<1250\Rightarrow \frac{(2n-1)\times 340}{4\times 0.85}<1250\] \[\Rightarrow \]\[(2n-1)<12.5\] Possible value of n = 1, 2, 3, 4, 5, 6 So, number of possible natural frequencies lie below 1250 Hz is 6.You need to login to perform this action.
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