question_answer

Equations of lines which passes through the points of intersection of the lines \[4x-3y-1=0\] and \[2x-5y+3=0\] and are equally inclined to the axes are

A) \[y\pm x=0\]            

B)   \[y-1=\pm 1(x-1)\]

C) \[x-1=\pm 2(y-1)\]     

D) None of these

Correct Answer: B

Solution :

Point of intersection of the lines \[4x-3y-1=0\] and \[2x-5y+3=0\]is \[(1,1)\]

\[\because \] the lines are equally inclined to the axes.

\[\therefore \]  angles will be either \[45{}^\circ \]or \[135{}^\circ \].

Hence, the required equation are \[y-1=\pm 1\left( x-1 \right)\]