(I) \[0.1\text{ }M\]\[CaC{{l}_{2}}\] has higher boiling point than\[0.1\text{ }M\]\[NaCl\]. |
(II) \[0.05\text{ }M\]\[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]has higher freezing point than \[0.1\text{ }M\]\[{{K}_{3}}[Fe{{(CN)}_{6}}].\] |
(III) \[0.1\text{ }M\]glucose exerts higher osmotic pressure than \[0.08\text{ }M\]\[C{{H}_{3}}COOH\](\[25%\] dissociated). |
(IV) Vapour pressure of \[0.05\text{ }M\]urea solution is greater than that of \[0.05\text{ }M\text{ }KCl\]solution. |
The CORRECT choice is |
A) I, III
B) II, IV
C) I, II, III
D) I, II, IV
Correct Answer: D
Solution :
[d] \[{{T}_{b}}\] is higher if im is higher \[{{T}_{f}}\]. is higher if im is lower, \[\pi \] is higher if im is higher. VP is higher if im is lower. \[CaC{{l}_{2}}:im=3\times 0.1;\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}:im=5\times 0.05;\] Glucose: \[im=1\times 0.1;\] \[NaCl:im=2\times 0.1;\] \[{{K}_{3}}[Fe{{(CN)}_{6}}]:im=4\times 0.1;\] \[C{{H}_{3}}COOH:im=(1+\alpha )m=1.25\times 0.08=0.1\] Urea: \[im=1\times 0.05;\] \[KCl:im=2\times 0.05=0.1\]You need to login to perform this action.
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