A) \[25%\]
B) \[20%\]
C) \[75%\]
D) \[37.5%\]
Correct Answer: C
Solution :
[c] Using equation \[PV=nRT\]Initial moles | Total final moles |
\[{{n}_{1}}=\] moles of \[N{{H}_{3}}\] | Moles formed from \[N{{H}_{3}}=\left( \frac{1}{2}+\frac{3}{2} \right){{n}_{1}}\] |
\[{{n}_{2}}=\] moles of \[{{N}_{2}}{{H}_{4}}\] | Moles formed from \[{{N}_{2}}{{H}_{4}}=(1+2){{n}_{2}}=3{{n}_{2}}\] |
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