A) \[\Delta G=0,\Delta S=+ve\]
B) \[\Delta G=0,\Delta S=-ve\]
C) \[\Delta G=+ve,\Delta S=0\]
D) \[\Delta G=-ve,\Delta S=+ve\]
Correct Answer: A
Solution :
: The change given is occurring at the boiling point of the liquid, where, at given pressure and temperature, the liquid-vapour system virtually remains at equilibrium and hence, \[\Delta G=0\]. Also due to absorption of heat as latent heat of vaporisation, or due to change from liquid to gaseous state where randomness has also increased, \[\Delta S>0\].You need to login to perform this action.
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