question_answer

Match the items given in column I with those in column II and choose the correct option given below.

	Column I (Reactions)		Column II (Products)
I.		P.
II.		Q.
III.		R.
IV.		S.

A) I - R    II - S   III - Q IV - P

B) I - P     II - Q  III - S  IV - R

C) I - Q    II - P   III - R IV - S

D) I - S     II - R   III - P  IV - Q

Correct Answer: C

Solution :

[c]           (I) (II) This produces \[C{{O}_{2}};\] the reaction is Kolbe reaction. (III)             Carbene also converts \[(-N{{H}_{2}})\] group to \[(-\overset{\oplus }{\mathop{N}}\,\equiv \overset{\bigcirc -}{\mathop{C}}\,-)\]group (Carbylamine reaction) and also adds to \[(C==C)\]bond of cyclopentane ring and undergoes Reimer-Tiemann reaction at o-position w.r.t \[(-OH)\] group in benzene ring. (IV) \[CC{{l}_{2}}BrI\xrightarrow{4NaOH}2NaCl+NaBr+NaI+C{{(OH)}_{4}}\]                           \[\xrightarrow{-2{{H}_{2}}O}C{{O}_{2}}\]