A) \[\frac{46}{3}\]
B) \[\frac{35}{4}\]
C) \[\frac{45}{4}\]
D) \[\frac{41}{4}\]
Correct Answer: C
Solution :
| Let total no. of obs =18 |
| Let mean of one group \[={{a}_{1}}=15\] |
| and mean of other group \[={{a}_{2}}\] |
| Given: Combined mean \[=\frac{40}{3}\] |
| Now, combined mean \[=\frac{\left( {{a}_{1}}\times 10 \right)+\left( {{a}_{2}}\times 8 \right)}{18}\] |
| \[\Rightarrow \,\,\frac{40}{3}=\frac{150+8{{a}_{2}}}{18}\Rightarrow {{a}_{2}}=\frac{45}{4}\] |
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