A) \[\frac{1}{3}xyz(x+y)(y+z)(z+x)\]
B) \[\frac{1}{4}xyz(x+y-z)(y+z-x)\]
C) \[\frac{1}{12}xyz(x-y)(y-z)(z-x)\]
D) none of these
Correct Answer: C
Solution :
[c]:
Use\[{{R}_{1}}\to {{R}_{1}}-{{R}_{2}}\]and\[{{R}_{2}}\to {{R}_{2}}-{{R}_{3}}\] and expanding long \[{{R}_{3}}\], we have, \[\frac{xyz}{12}(x-y)(y-z)(z-x)\]
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