A) 500
B) 1000
C) 1250
D) 100
Correct Answer: C
Solution :
[c] : AC power gain is ratio of change in output power to the change in input power. AC power gain \[=\frac{Change\text{ }in\text{ }output\text{ }power}{Change\text{ }in\text{ }input\text{ }power}=\frac{\Delta {{V}_{0}}\times \Delta {{I}_{c}}}{\Delta {{V}_{i}}\times \Delta {{I}_{b}}}\] \[=\left( \frac{\Delta {{V}_{0}}}{\Delta {{V}_{i}}} \right)\times \left( \frac{\Delta {{I}_{c}}}{\Delta {{I}_{b}}} \right)={{A}_{V}}\times {{\beta }_{AC}}\]where \[{{A}_{V}}\]is voltage gain and \[{{(\beta )}_{AC}}\]is AC current gain. Also, \[{{A}_{V}}={{\beta }_{AC}}\times \]resistance gain \[\left( \frac{{{R}_{0}}}{{{R}_{i}}} \right)\] Given, \[{{A}_{V}}=50,{{R}_{0}}=200\Omega ,{{R}_{i}}=100\Omega \] Hence, \[50={{\beta }_{AC}}\times \frac{200}{100}\] \[\therefore \]\[{{\beta }_{AB}}=25\] Now, AC power gain \[={{A}_{C}}\times {{\beta }_{AC}}=50\times 25=1250\]
You need to login to perform this action.
You will be redirected in
3 sec
