A) \[0.025\,\text{m}\,{{\text{s}}^{-2}}\]
B) \[0.25\,\text{m}\,{{\text{s}}^{-2}}\]
C) \[0.50\,\text{m}\,{{\text{s}}^{-2}}\]
D) \[500\,\text{m}\,{{\text{s}}^{-2}}\]
Correct Answer: A
Solution :
[a] : Here, M = 2000 kg, m = 10 g = 0.01 kg Force on car = rate of change of momentum of bullets \[F=nmv=10\times 0.01\times 500=50N\] \[a=\frac{F}{M}=\frac{50}{2000}=0.025m{{s}^{-2}}\]
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