JEE Main & Advanced Sample Paper JEE Main - Mock Test - 18

  • question_answer
    Let \[{{z}_{1}}\] and \[{{z}_{2}}\] be complex numbers, then \[|{{z}_{1}}+{{z}_{2}}{{|}^{2}}+|{{z}_{1}}-{{z}_{2}}{{|}^{2}}\]is equal to:

    A) \[|{{z}_{1}}{{|}^{2}}+|{{z}_{2}}{{|}^{2}}\]         

    B)   \[2(|{{z}_{1}}{{|}^{2}}+|{{z}_{2}}{{|}^{2}})\]

    C) \[2(z_{1}^{2}+z_{2}^{2})\]        

    D)   \[4{{z}_{1}}{{z}_{2}}\]

    Correct Answer: B

    Solution :

    We know, \[|{{z}_{1}}+{{z}_{2}}{{|}^{2}}=|{{z}_{1}}{{|}^{2}}+|{{z}_{2}}{{|}^{2}}+2\operatorname{Re}\,({{z}_{1}}{{\bar{z}}_{2}})\] \[|{{z}_{1}}-{{z}_{2}}{{|}^{2}}=|{{z}_{1}}{{|}^{2}}+|{{z}_{2}}{{|}^{2}}-2\operatorname{Re}\,({{z}_{1}}{{\bar{z}}_{2}})\] \[\Rightarrow \,\,|{{z}_{1}}+{{z}_{2}}{{|}^{2}}+|{{z}_{1}}-{{z}_{2}}{{|}^{2}}=2(|{{z}_{1}}{{|}^{2}}+|{{z}_{2}}{{|}^{2}})\]


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