A) \[f\left( 4\sqrt{2} \right)\]
B) \[f\left( 3\sqrt{2} \right)\]
C) \[f\left( 2\sqrt{2} \right)\]
D) \[f\left( \sqrt{2} \right)\]
Correct Answer: A
Solution :
Given, \[f(x)={{x}^{2}}-3\] Now, \[f(-1)={{\left( -1 \right)}^{2}}-3=-2\] \[\Rightarrow \,\,fof\,\,\left( -1 \right)=f\left( -2 \right)={{\left( -2 \right)}^{2}}-3=1\] \[\Rightarrow \,\,fofof\,\,\left( -1 \right)=f\left( 1 \right)={{1}^{2}}-3=-2\] .....(i) Similarly, \[fofof(0)=33\] .....(ii) and \[fofof(1)=-2\] .....(iii) Adding (i), (ii) and (iii), we get \[fofof\left( -1 \right)+fofof(0)+fofof(1)=-2+33-2=29\] \[=f\left( 4\sqrt{2} \right).\]
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