JEE Main & Advanced Sample Paper JEE Main - Mock Test - 21

  • question_answer
    The coefficient of 1/x in the expansion of \[{{(1+x)}^{n}}{{\left( 1+\frac{1}{x} \right)}^{n}}\] is

    A) \[\frac{n!}{(n-1)!(n+1)!}\]          

    B) \[\frac{(2n)!}{(n-1)!(n+1)!}\]

    C) \[\frac{2n!}{(2n-1)!(2n+1)!}\]

    D) None of these

    Correct Answer: B

    Solution :

    [b]: Clearly, \[{{(1+x)}^{n}}{{=}^{n}}{{C}_{0}}{{+}^{n}}{{C}_{1}}x{{+}^{n}}{{C}_{2}}{{x}^{2}}+....{{+}^{n}}{{C}_{n}}{{x}^{n}}\] \[{{\left( 1+\frac{1}{x} \right)}^{n}}{{=}^{n}}{{C}_{0}}{{+}^{n}}{{C}_{1}}\frac{1}{x}{{+}^{n}}{{C}_{2}}\frac{1}{{{x}^{2}}}+....{{+}^{n}}{{C}_{n}}{{\left( \frac{1}{x} \right)}^{n}}\] Now, required coefficient of \[\frac{1}{x}\]is given by \[^{n}{{C}_{0}}^{n}{{C}_{1}}{{+}^{n}}{{C}_{1}}^{n}{{C}_{2}}+...{{+}^{n}}{{C}_{n-1}}^{n}{{C}_{n}}=\frac{(2n)!}{(n-1)!(n+1)!}\]


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