• # question_answer Let R = {(3, 3), (6, 6), (9, 9), (12, 12), (6, 12), (3, 9), (3, 12), (3, 6)} be a relation on the set A = {3, 6, 9, 12}. The relation is A) reflexive and transitive only B) reflexive only C) an equivalence relation D) reflexive and symmetric only

[a] : Since (3, 3), (6. 6), (9, 9). (12, 12)$\in R$ Hence R is reflexive $\because$(3, 6), (6, 12) and (3, 12) $\in R$. Therefore R is transitive. $\because$(3, 6) ER but (6, 3) $\notin R$hence R is not symmetric.