A) \[\frac{\pi }{6}\]
B) 0
C) \[\frac{\pi }{3}\]
D) \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
[d]: The d.rs of the lines are \[\frac{1}{2},\frac{1}{3},-1\]and\[\frac{1}{6},-1,-\frac{1}{4}\]or 3, 2.-6 and 2.-12,-3 \[3\times 2+2\times (-12)+(-6)(-3)=0.\] \[\therefore \]\[\theta =\frac{\pi }{2}\]
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