JEE Main & Advanced
Sample Paper
JEE Main - Mock Test - 24
question_answer
A physical quantity P is given by \[P=\frac{{{A}^{3}}{{B}^{\frac{1}{2}}}}{{{C}^{-\,4}}{{D}^{\frac{3}{2}}}}\]. The quantity which brings in the maximum percentage error in P is
A)A
B)B
C)C
D) D
Correct Answer:
C
Solution :
Quantity C has maximum power. So it brings maximum error in P.