JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    20 soldiers are standing in a row. The captain wants to make a team of 7 out of them for a mission. In how many ways can the captain select them such that at least one soldier finds the soldier next to him also selected.

    A) \[^{20}{{C}_{7}}\]                 

    B)        \[^{14}{{C}_{7}}\]                  

    C) \[^{20}{{C}_{7}}{{-}^{13}}{{C}_{7}}\]         

    D)        \[^{20}{{C}_{7}}{{-}^{13}}{{C}_{7}}\]

    Correct Answer: D

    Solution :

    [d] Required number of ways
    = Total number of ways without any restriction
    Number of ways in which no two consecutive soldiers are selected
    Let \[{{x}_{1}}\] be the number of soldiers before first soldier selected.
    Also, let \[{{x}_{2}},{{x}_{3}},{{x}_{4}},{{x}_{5}},{{x}_{6}}\]and \[{{x}_{7}}\] be the number of
    soldiers between \[{{1}^{st}}\] and \[{{2}^{nd}},\] \[{{2}^{nd}}\] and \[{{3}^{rd}}\], \[{{3}^{rd}}\] and \[{{4}^{th}},\] \[{{4}^{th}},\] and \[{{5}^{th}},\] \[{{5}^{th}},\] and \[{{6}^{th}},\]\[{{6}^{th}},\] and \[{{7}^{th}},\] respectively.
    And let \[{{x}_{8}}\] be the number of soldiers after the \[{{7}^{th}}\] solider selected.
    Now \[{{x}_{1}}+{{x}_{2}}+....+{{x}_{8}}=13\]
    Also \[{{x}_{1}},{{x}_{8}}\ge 0\] and \[{{x}_{2}},{{x}_{3}},....{{x}_{7}}\ge 1\]
    \[\Rightarrow \,\,\,{{x}_{1}}+{{y}_{2}}+.....+{{y}_{7}}+{{x}_{8}}=7,\]
    where \[{{y}_{2}},{{y}_{3}},............,{{y}_{7}}\ge 0\].
    Number of solutions of above equation
    \[{{=}^{8+7-1}}{{C}_{8-1}}{{=}^{14}}{{C}_{7}}\]
    \[\therefore \] Required number of ways \[{{=}^{20}}{{C}_{7}}{{-}^{14}}{{C}_{7}}\]


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