A) \[{{e}_{1}}+2{{e}_{2}}\]
B) \[{{e}_{1}}+{{e}_{2}}\]
C) \[{{e}_{1}}-2{{e}_{2}}\]
D) \[{{e}_{2}}-{{e}_{1}}\]
Correct Answer: A
Solution :
[a] \[h=\frac{1}{2}g{{t}^{2}}\,\,\,\,\,\Rightarrow \,\,\,\,g=\frac{2h}{{{t}^{2}}}\] then \[\frac{\Delta g}{g}\times 100=\left( \frac{\Delta h}{h}+2\frac{\Delta t}{t} \right)\times 100={{e}_{1}}+2{{e}_{2}}\]
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