| A forced oscillator is acted upon by a force \[F={{F}_{0}}\,\sin \,\omega t\]. The amplitude of oscillation is given by \[\frac{55}{\sqrt{2{{\omega }^{2}}-36\omega +9}}\]. |
| The resonant angular frequency is |
A) 2 units
B) 9 units
C) 18 units
D) 36 units
Correct Answer: B
Solution :
At resonance, amplitude of oscillation is maximum \[\Rightarrow \,\,\,2{{\omega }^{2}}- 36\omega + 9 \,is \,minimum\] \[\Rightarrow \,\,\,4\omega - 36 = 0 \left( derivative is zero \right)\] \[\Rightarrow \,\,\,\,\omega =9\]
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