A) 2 : 1
B) 4 : 1
C) 9 : 1
D) 8 : 1
Correct Answer: C
Solution :
[c] : If \[{{W}_{1}}\] and \[{{W}_{2}}\]are widths of two slits then \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{{{W}_{1}}}{{{W}_{2}}}=4\] Also,\[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{A_{1}^{2}}{A_{2}^{2}}\therefore \frac{A_{1}^{2}}{A_{2}^{2}}=4\]or\[\frac{{{A}_{1}}}{{{A}_{2}}}=2\] \[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{{{A}_{1}}+{{A}_{2}}}{{{A}_{1}}-{{A}_{2}}} \right)}^{2}}\] \[={{\frac{\left( \frac{{{A}_{1}}}{{{A}_{2}}}+1 \right)}{{{\left( \frac{{{A}_{1}}}{{{A}_{2}}}-1 \right)}^{2}}}}^{2}}=\frac{{{(2+1)}^{2}}}{{{(2-1)}^{2}}}=\frac{9}{1}\]
You need to login to perform this action.
You will be redirected in
3 sec
