question_answer

\[{{F}_{2}}\] can be prepared by reacting hexafluoro magnate (IV) with antimony pentafluoride as: \[{{K}_{2}}Mn{{F}_{6}}+Sb{{F}_{5}}\xrightarrow{{}}KSb{{F}_{6}}+Mn{{F}_{3}}+{{F}_{2}}\] The number of equivalent \[{{K}_{2}}Mn{{F}_{6}}\] required to react completely with one mole of \[Sb{{F}_{5}}\] in the given reaction is _____.

Answer:

0.5