A) 2 and 2
B) 3 and 3
C) 4 and 3
D) 3 and 4
Correct Answer: C
Solution :
[c] Loschmidt number\[=2.687\times {{10}^{25}}{{m}^{-3}}\] = 4 significant figures Boltzmann constant (k) =\[1.38\times {{10}^{-23}}J{{K}^{-1}}\] = 3 significant figures.
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