question_answer

Compound \[(A)({{C}_{4}}{{H}_{8}}{{O}_{3}})\] reacts with \[NaHC{{O}_{3}}\]and evolves \[C{{O}_{2}}\left( g \right)\]. (A) reacts with LAH to give a compound (B) which is a chiral. The structure of (A) is

A)          

B)

C)        

D)

Correct Answer: A

Solution :

[a] \[NaHC{{O}_{3}}\] test shows the presence of the \[(-COOH)\] group, and from the structure given in the problem, only the compound in (1) on reduction with LAH gives achiral product.      The compounds in (2), (3), and (4) with LAH will give chiral product. So the answer is (1).