A) \[{{\operatorname{H}}_{2}}O\,\,and\,\,N{{a}_{2}}O\]
B) \[\operatorname{MgO} and N{{a}_{2}}O\]
C) \[{{\operatorname{Na}}_{2}}O\,\,and\,\,BaO\]
D) \[\operatorname{SnC}{{l}_{2}}\,\,and\,\,SnC{{l}_{4}}\]
Correct Answer: D
Solution :
\[SnC{{l}_{2}}\] \[SnC{{l}_{4}}\] \[119:2\times 35.5\] \[119:4\times 35.5\] Chlorine ratio in both compounds is \[=\,\,2\times 35.5 :4\times 35.5=1:2\]
You need to login to perform this action.
You will be redirected in
3 sec
