A) the electronegativity of F is greater than that of O
B) \[{{H}_{2}}O\] involves hydrogen bonding whereas \[Be{{F}_{2}}\] is a discrete molecule
C) \[{{H}_{2}}O\] is linear and \[Be{{F}_{2}}\] is angular
D) \[{{H}_{2}}O\] is angular and \[Be{{F}_{2}}\] is linear
Correct Answer: D
Solution :
In a linear symmetrical molecule like \[Be{{F}_{2}}\], the bond angle between three atoms is \[180{}^\circ \], hence the polarity due to one bond is cancelled by the equal polarity due to other bond, while it is not so in angular molecules, like \[{{H}_{2}}O\].
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