question_answer

In figure-1 shown, \[{{m}_{1}}\] vertically oscillates with angular frequency\[{{\omega }_{1}}\]. Now the system is inverted so that \[{{m}_{2}}\] is at top it oscillated vertically it oscillates with angular frequency\[{{\omega }_{2}}\]. If it is kept on smooth ground as shown in figure-2, new angular frequency is                     

A) \[\frac{{{\omega }_{1}}+{{\omega }_{2}}}{2}\]           

B)        \[\sqrt{{{\omega }_{1}}{{\omega }_{2}}}\]

C) \[\sqrt{\omega _{1}^{2}+\omega _{2}^{2}}\] 

D)        \[\frac{{{\omega }_{1}}{{\omega }_{2}}}{{{\omega }_{1}}+{{\omega }_{2}}}\]