A) \[C{{H}_{3}}CH=CHC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
B) \[{{C}_{10}}{{H}_{22}}\]
C) \[C{{H}_{3}}-C{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{4}}C\]
Correct Answer: A
Solution :
Only alkenes and alkynes (or compounds having \[C=C\,\,or\,\,C\equiv C\]) decolourise alkaline \[\operatorname{KMn}{{O}_{4}}\] solution. Only is alkene, other three are alkanes.
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