A) \[[{{M}^{2}}{{L}^{3}}{{T}^{-2}}{{A}^{2}}]\]
B) \[[ML{{T}^{-4}}]\]
C) \[[M{{L}^{3}}{{T}^{-2}}]\]
D) \[[{{M}^{-1}}{{L}^{2}}{{A}^{-2}}]\]
Correct Answer: B
Solution :
[b] \[\left[ \frac{{{E}^{2}}}{{{\mu }_{0}}} \right]\,=\,\left[ \frac{{{\varepsilon }_{0}}{{E}^{2}}}{{{\varepsilon }_{0}}{{\mu }_{0}}} \right]\] \[=\left[ \frac{energy/volume}{{{(1/speed\,\,of\,\,light)}^{2}}} \right]\] \[=\left[ \frac{energy\,\,{{(speed)}^{2}}}{volume} \right]\] \[=\left[ \frac{M{{L}^{2}}{{T}^{-2}}{{L}^{2}}{{T}^{-2}}}{{{L}^{3}}} \right]\] \[[ML{{T}^{-4}}]\]
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