A) 60 days
B) 15 days
C) 30 days
D) 50 days
Correct Answer: D
Solution :
[d] Active fraction at instant \[{{t}_{2}},\] \[^{\frac{1}{{{2}^{{{t}_{2}}/{{T}_{1/2}}}}}=\frac{1}{3}}\] Active fraction at instant \[{{t}_{1}},\] \[\frac{1}{{{2}^{{{t}_{1}}/{{T}_{1/2}}}}}=\frac{2}{3}\] \[\Rightarrow \,\,\,\,\frac{{{2}^{{{t}_{2}}/{{T}_{1/2}}}}}{{{2}^{{{t}_{1}}/{{T}_{1/2}}}}}=2\Rightarrow {{2}^{\frac{{{t}_{2}}-{{t}_{1}}}{{{T}_{1/2}}}}}={{2}^{1}}\] \[\Rightarrow \,\,\,\,{{t}_{2}}-{{t}_{1}}={{T}_{1/2}}=50\] days
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