A) 1
B) 3
C) 5
D) 7
Correct Answer: B
Solution :
[b] The cell reaction is \[{{H}_{2(g)}}+{{I}_{2(s)}}2H_{(aq)}^{+}2I_{(aq)}^{-}\] \[0.7714=0.535-\frac{0.0591}{2}log\frac{{{[{{H}^{+}}]}^{2}}{{[{{I}^{-}}]}^{2}}}{{{P}_{{{H}_{2}}}}}\] \[pH=3\]You need to login to perform this action.
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