A) \[2\pi m{{k}^{2}}{{r}^{2}}\]
B) \[m{{k}^{2}}{{r}^{2}}t\]
C) \[\frac{(m{{k}^{4}}{{r}^{2}}{{t}^{5}})}{3}\]
D) Zero
Correct Answer: B
Solution :
[b] \[{{a}_{c}}={{k}^{2}}r{{t}^{2}}\Rightarrow \frac{{{v}^{2}}}{r}={{k}^{2}}r{{t}^{2}}\] \[\Rightarrow \,\,\,{{v}^{2}}={{k}^{2}}{{r}^{2}}{{t}^{2}}\Rightarrow v=krt\Rightarrow {{a}_{r}}=\frac{dv}{dt}=kr\] \[P=\int{m\,\,{{\overset{\to }{\mathop{a}}\,}_{r}}}\overset{\to }{\mathop{v}}\,=m(kr).\,(krt)=m{{k}^{2}}{{r}^{2}}t\]You need to login to perform this action.
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