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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 33

  • question_answer
    \[N{{H}_{4}}HS(s)\rightleftharpoons N{{H}_{3}}(g)+{{H}_{2}}S(g)\] The equilibrium pressure at \[25{}^\circ C\] is 0.660 atm. What is \[{{K}_{p}}\] for the reaction?

    A) 0.109      

    B)        0.218

    C) 1.89                 

    D)        2.18

    Correct Answer: A

    Solution :

    [a] \[\underset{-}{\mathop{N{{H}_{4}}HS(s)}}\,\underset{P}{\mathop{N{{H}_{3}}(g)}}\,+\underset{P}{\mathop{{{H}_{2}}S(g)}}\,\] Equ. pressure 2P = 0.660 P= 0.330 \[Kp={{P}_{N{{H}_{3}}}}.{{P}_{{{H}_{2}}S}}\] \[=0.33\times 0.33=0.109\]   


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