JEE Main & Advanced Sample Paper JEE Main - Mock Test - 36

  • question_answer
    10 g of ice at \[0{}^\circ C\] is mixed with 100 g of water at\[50{}^\circ C\]. What is the resultant temperature of mixture -

    A) \[31.2{}^\circ C\]

    B)                    \[32.8{}^\circ C\]

    C) \[36.7{}^\circ C\]          

    D)        \[38.2{}^\circ C\]

    Correct Answer: D

    Solution :

    [d] \[{{\theta }_{mix}}=\frac{{{m}_{w}}{{\theta }_{w}}-\frac{{{m}_{i}}{{L}_{i}}}{{{c}_{w}}}}{{{m}_{i}}+{{m}_{w}}}\] \[=\frac{100\times 50-10\times \frac{80}{1}}{10+100}\] \[=38.2{}^\circ C\]


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