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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 38

  • question_answer
    The primary and secondary coils of a transformer have 50 turns and 1500 turns respectively. If the magnetic flux/linked with the primary coil is given by \[\phi ={{\phi }_{0}}+4t,\] where \[\phi \] is in Webers, t is time in seconds and \[{{\phi }_{0}}\] is a constant, the output voltage across the secondary coil is

    A) 30 volts        

    B)        90 volts              

    C)   120 volts          

    D)        220 volts

    Correct Answer: C

    Solution :

    [c] Induced emf in primary coil \[{{E}_{p}}=\frac{d\phi }{dt}=\frac{d}{dt}\,\left( {{\phi }_{0}}+4t \right)=4\,volt\] Induced emf in secondary coil \[\frac{{{E}_{S}}}{{{E}_{P}}}=\frac{{{N}_{S}}}{{{N}_{P}}}\Rightarrow \,\,\,\,\frac{{{E}_{S}}}{4}=\frac{1500}{50}\Rightarrow {{E}_{S}}=120\,\,volt\]  


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