JEE Main & Advanced Sample Paper JEE Main - Mock Test - 38

  • question_answer
    The hybridization states of the nitrogen atoms in pyridine, piperidine and pyrrole are respectively

    A) \[s{{p}^{2}},\text{ }s{{p}^{3}}and\text{ }s{{p}^{2}}\]        

    B) \[s{{p}^{2}},\text{ }s{{p}^{3}}and\text{ }s{{p}^{3}}\]

    C) \[s{{p}^{3}},\text{ }s{{p}^{3}}and\text{ }s{{p}^{3}}\] 

    D)        \[s{{p}^{2}},\text{ }s{{p}^{2}}and\text{ }s{{p}^{2}}\]

    Correct Answer: A

    Solution :

    [a] \[s{{p}^{2}},\text{ }s{{p}^{3}}\] and \[s{{p}^{2}}\]


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