(i) Simple cubic cell: \[Radius=\frac{a}{2}\] |
(ii) Face centred cubic cell: \[Radius=\frac{a}{3\sqrt{3}}\] |
(iii) Body centred cubic cell: \[Radius=\frac{\sqrt{3}}{4}a\] |
A) (i)
B) (iii)
C) (ii)
D) (i) and (ii)
Correct Answer: C
Solution :
For fcc, radius of the atom \[=\,\,\frac{a}{2\sqrt{2}}\].You need to login to perform this action.
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