JEE Main & Advanced Sample Paper JEE Main - Mock Test - 40

  • question_answer
    A radioactive decay chain starts from \[_{93}N{{p}^{237}}\]  and produces \[_{90}T{{h}^{22}}^{9}\] by successive emissions. The emitted particles can be-

    A) Two \[\alpha \]-particles and one \[\beta \]-particles

    B) Three \[{{\beta }^{+}}\] particles

    C) One \[\alpha \]-particle and two \[{{\beta }^{+}}\] particles

    D) One \[\alpha \]-particle and two \[{{\beta }^{-}}\] particles

    Correct Answer: A

    Solution :

    [a] By using \[{{n}_{\alpha }}=\frac{A-A'}{4}\] and \[n\beta =2{{n}_{\alpha }}-Z+Z'\]


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