A) donate proton to form \[{{H}_{2}}B{{O}_{3}}^{-}\]
B) accept proton of form \[{{H}_{4}}B{{O}_{3}}^{+}\]
C) donate OH- to form \[{{H}_{2}}B{{O}_{2}}^{+}\]
D) accept OH- to form \[{{[B{{(OH)}_{4}}]}^{-}}\]
Correct Answer: D
Solution :
\[{{H}_{3}}B{{O}_{3}}\] acts as a Lewis acid and accepts \[O{{H}^{-}}\] ions to form \[{{[B{{(OH)}_{4}}]}^{-}}\]
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