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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 40

  • question_answer
    The molal elevation constant of water \[=0.52{}^\circ C\,\,kg\,\,mo{{l}^{-1}}\] . The boiling point of \[1.0\] molal aqueous \[KCl\] solution (assuming complete dissociation of \[KCl\]), therefore should be

    A) \[100.52{}^\circ C\]                  

    B) \[101.04{}^\circ C\]

    C) \[99.48{}^\circ C\]       

    D)        \[98.96{}^\circ C\]

    Correct Answer: B

    Solution :

    \[\Delta {{T}_{b}}={{K}_{b}}\times m\times i=0.52\times 1\times 2=1.04\] \[\therefore \,\,\Delta {{T}_{b}}=100+1.04=101.04{}^\circ C\]


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