This follows first order kinetics. The rate constant is \[2.714\times {{10}^{-3}}{{s}^{--1}}.\]The initial concentration of cyclopropane is\[0.29\text{ }M\]. What will be the concentration of cyclopropane after 100s?
A) \[0.035\text{ }M\]
B) \[0.22\text{ }M\]
C) \[0.145M\]
D) \[0.0018\text{ }M\]
Correct Answer: B
Solution :
\[k=\frac{2.303}{t}\log \frac{a}{(a-x)}\] \[(a-x)\] is the concentration left after 100 sec. \[2.7\times {{10}^{-3}}=\frac{2.303}{100}\log \frac{0.29}{(a-x)}\] \[\Rightarrow \,\,\frac{0.27}{2.303}=\log \frac{0.29}{(a-x)}\Rightarrow 0.117=\log \frac{0.29}{(a-x)}\] \[\Rightarrow \,\,(a-x)=0.22M\].
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