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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 41

  • question_answer
    A binary solid \[\left( {{A}^{+}}{{B}^{-}} \right)\] has zinc blende structure with \[{{B}^{-}}\] ions constituting the lattice and \[{{A}^{+}}\] ions occupying 25% tetrahedral holes. The formula of solid is -

    A) AB                   

    B)        \[{{A}_{2}}B\]

    C) \[A{{B}_{2}}\]         

    D)        \[A{{B}_{4}}\]

    Correct Answer: C

    Solution :

    [c] Suppose no. of \[{{B}^{-}}\] ions = N \[\therefore \] no. of tetrahedral holes = 2N As 25% tetrahedral holes are occupied by \[{{A}^{+}}\] ions. \[\therefore \] no. of \[{{A}^{+}}\] inos \[=\frac{2N}{4}=\frac{N}{2}\] \[\therefore \] Ratio of \[{{A}^{+}}:{{B}^{-}}=\frac{N}{2}:N\Rightarrow 1:2\] \[\therefore \] the formula is \[A{{B}_{2}}\]          


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